Công thức vật lý - Vật Lý 24/7

$x=Nm{i}_2=Nn{i}_1$$\Rightarrow i_2=\frac{{\lambda }_2}{{\lambda }_1}{i}_1$

$$\begin{gathered} x_M\le x\le x_N \\ \Rightarrow N_{s trùng}=\left[\frac{OM}{i}\right]+\left[\frac{ON}{i}\right]+1 khác phía \end{gathered}$$

$$\begin{gathered} L=x=n\frac{{\lambda }_{1}D}{a}=m\frac{{\lambda }_{2}D}{a} \\ =\left(n_{s1}+1\right)i_1=\left(n_{s2}+1\right)i_2 \end{gathered}$$

$N_{tối}=N_{t1}+N_{t2}-N_{t trùng}=2\left[\frac{L}{2i_1}+\frac{1}{2}\right]+2\left[\frac{L}{2i_2}+\frac{1}{2}\right]-2\left[\frac{L}{2x}+\frac{1}{2}\right]$

$N_{s quan sát}=N_{s1}+N_{s2}-N_{s trùng}=2\left[\frac{L}{2i_1}\right]+2\left[\frac{L}{2i_2}\right]-2\left[\frac{L}{2x}\right]+1$

$N_{s đơn sắc}=N_{s1}+N_{s2}-2N_{s trùng}=2\left[\frac{L}{2i_1}\right]+2\left[\frac{L}{2i_2}\right]-4\left[\frac{L}{2x}\right]$

$N_{s trùng}=2\left[\frac{L}{2x}\right]+1$

$\frac{{\lambda }_1}{{\lambda }_2}=\frac{m}{n}$

$\Rightarrow x=\frac{m}{2}\frac{{\lambda }_{2}D}{a}=\frac{n}{2}\frac{{\lambda }_{1}D}{a}$

$\frac{{\lambda }_1}{{\lambda }_2}=\frac{k_2-0,5}{k_1-0,5}=\frac{m}{n}=\frac{0,5m}{0,5n}=...=\frac{{\displaystyle \frac{2a+1}{2}m}}{{\displaystyle \frac{2a+1}{2}n}}$

$\Rightarrow x=0,5m\frac{{\lambda }_{2}D}{a}=0,5n\frac{{\lambda }_{1}D}{a}$

$\frac{{\lambda }_1}{{\lambda }_2}=\frac{k_2}{k_1}=\frac{m}{n}=\frac{2m}{2n}=...=\frac{am}{an}$

$\Rightarrow x=m\frac{{\lambda }_{2}D}{a}=n\frac{{\lambda }_{1}D}{a}$

$0,38.\frac{k_1}{k_2}\le {\lambda }_2\le 0,76.\frac{k_1}{k_2}$ : sáng trùng sáng

Khi ${\lambda }_2$ thuộc khoảng bước sóng thì công thức đổi vị trí ${\lambda }_2 và {\lambda }_1;k_{1}và k_2$